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(D) The stability of carbocations is determined by the electronic effects of substituents attached to the benzene ring.$1$. $p-CH_3O-C_6H_4-CH_2^+$ $(

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$B > C > A > D$

Vedclass · Answer

(D) The stability of carbocations is determined by the electronic effects of substituents attached to the benzene ring.$1$. $p-CH_3O-C_6H_4-CH_2^+$ $(B)$: The $-OCH_3$ group at the para position exerts a strong $+M$ (mesomeric) effect,which significantly stabilizes the positive charge.$2$. $C_6H_5-CH_2^+$ $(C)$: This is the unsubstituted benzyl carbocation,stabilized only by resonance with the phenyl ring.$3$. $m-CH_3O-C_6H_4-CH_2^+$ $(A)$: The $-OCH_3$ group at the meta position does not exert a $+M$ effect. Instead,it exerts a $-I$ (inductive) effect,which destabilizes the carbocation compared to the unsubstituted benzyl carbocation.$4$. $p-NO_2-C_6H_4-CH_2^+$ $(D)$: The $-NO_2$ group at the para position exerts both a strong $-M$ and $-I$ effect,which strongly destabilizes the carbocation.Therefore,the order of stability is $B > C > A > D$.

The decreasing order of stability of the following carbocations is:
$A$. $m-CH_3O-C_6H_4-CH_2^+$
$B$. $p-CH_3O-C_6H_4-CH_2^+$
$C$. $C_6H_5-CH_2^+$
$D$. $p-NO_2-C_6H_4-CH_2^+$

Similar Questions

Stability order of the following carbocations:
$(i) CH_3 - C^{+}(OCH_3) - CH_3$
$(ii) CH_3 - C^{+}(CH_3) - CH_3$
$(iii) CH_3 - NH - C^{+}H_2$
$(iv) CH_3 - C^{+}H_2$

The increasing order of stability of the following free radicals is:

Which of the following is the least stable carbocation?

Which of the following carbocations lacks hyperconjugative stability?

The correct order of stability of the carbocations given below is:

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The decreasing order of stability of the following carbocations is:$A$. $m-CH_3O-C_6H_4-CH_2^+$$B$. $p-CH_3O-C_6H_4-CH_2^+$$C$. $C_6H_5-CH_2^+$$D$. $p-NO_2-C_6H_4-CH_2^+$